Today we will discuss the formation of Boron trifluoride BF3 molecule. Let’s write the ground state configuration of central atom B and F.
5B – 1s2, 2s2, 2p1
9F – 1s2, 2s2, 2p5

5B – 1s2, 2s1, 2p2
Now B chooses one 2sorbital and two of the 2p orbital and hybridises them to get three hybridised sp2orbitals. These three hybridised sp2orbitals get arranged in a triangular shape (fan shaped). Now F atoms come closer to B so that their 2pzorbitals get overlapped with these hybridised sp2 orbitals and make bonds. Thus BF3 molecule is formed by bonding between three sp2orbitals of B and p of 3 F atoms.

2Be – 1s2, 2s2
9F – 1s2, 2s2, 2p5
Be has 2 paired electrons but it needs 2 unpaired electrons to combine with unpaired electrons of two atoms of F. Outer orbit of Be has two orbitals s and p so it promotes its one electron to the p orbital. Now it’s excited state configuration will be
Be has 2 paired electrons but it needs 2 unpaired electrons to combine with unpaired electrons of two atoms of F. Outer orbit of Be has two orbitals s and p so it promotes its one electron to the p orbital. Now it’s excited state configuration will be
2Be – 1s2, 2s1, 2p1
With the promotion of electron, 2s orbital also gets promoted to the level of 2p orbital. Now Be picks ones and one p orbital and hybridises them to get two sphybridised orbitals. These two sphybridised orbitals get arranged in a linear shape.

Up to now we have discussed those molecules which have single covalent bonds. In previous post of covalent compounds we have seen two more type of covalent bonds double bond and triple bond. How are these bonds formed? You know these bonds are formed by sharing of 4 and 6 valence electrons respectively. What is the role of orbitals in their formation? We will see the sights of orbitals in the formation of double and triple bond in the next post.
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