Linus Pauling proposed the Valence Bond Theory (VBT) to explain how valence electrons of different atoms combine to form a molecule. He said that unpaired electrons (valence electrons) of one atom combines with unpaired electrons of other atoms and thus forms a molecule. I am not going to puzzle you with rules; we will learn the rules by examples.
Let’s take an example of H2O molecule and see how it is formed by O and H. To understand it we have to look at the electronic configurations of O and H.
8O – 1s2, 2s2, 2p4
1H – 1s1
Now place these electrons to their corresponding orbitals. You can see here that O is the central atom and it has 6 valence electrons, out of which 2 are unpaired. Each of the unpaired electron gets paired with 1 electron of H. Thus O and H share electrons and form H2O molecule. In this pairing they also follow the ‘Pauli Exclusion Principle’ which means the spin of both paired electrons must be opposite.
Now take another example of CH4. Write the electronic configurations of C and H.
6C – 1s2, 2s2, 2p2
1H – 1s1
After placing these electrons to their corresponding orbitals you will find that C has 4 valence electrons, out of which only 2 are unpaired. But to complete its octet it needs 4 unpaired electrons to get paired with 4 atoms of H. To accomplish this C supplies some energy to its paired electrons and promotes one of them to the empty p orbital so that C has 4 unpaired electrons. Now its electronic configuration becomes:
6C – 1s2, 2s1, 2p3
This new configuration is called the excited state configuration and the previous configuration is known as the ground state configuration.
Let’s practice it with one more example of NH3. Write the electronic configurations of N and H.
7N – 1s2, 2s2, 2p3
1H – 1s1
At this stage when VBT explained the formation of molecule a new question arose. The bonding electrons or paired electrons are placed in the orbitals of the central atom, which means the orbitals of the central atom decide the shape of the molecule. In H2O molecule bonding electrons are placed in two p orbitals of O. These two p orbitals are at right angle to each other but the shape of H2O molecule is bent and angle is 104°27′. Similarly in CH4 molecule the question arises that how one spherical s orbital and three dumbbell shaped p orbitals which are at right angle to each other can give tetrahedral shape to the CH4 molecule?
In answer to these questions scientists proposed the phenomenon of Hybridization. it is similar to the process of Hybridization some of you have used or listened in gardening. In our next post we will learn about Hybridization and see how does this phenomenon solve the mystery of molecule?
This work is licensed under the Creative Commons Attribution- NonCommercial- NoDerivatives 4.0 International License. To view a copy of this license, visit http://creativecommons.org/licenses/by-nc-nd/4.0/.
No comments:
Post a Comment