In the last post we separated group IIB cations from IIA cations by using yellow ammonium polysulphide (NH4)2Sx solution, which dissolves the IIB cations. By doing this we obtained them in the form of filtrate. In the filtrate, the cations are in the form of thiosalts (NH4)3AsS4, (NH4)2SbS4, and (NH4)2SnS3 and for further analysis we have to dissociate the salts, remove excess of sulphur and re-precipitate the cations.
How to re-precipitate IIB cations: Add hydrochloric acid HCl to the filtrate until it becomes slightly acidic (test with litmus paper, acid turns blue litmus into red) then warm it and stir for 1-2minutes. It dissociates thiosalts and precipitates excess of sulphur in the form of fine white or yellow precipitate. If a yellow or orange flocculant (colloidal) precipitate is obtained, it may contain As2S5, As2S3, Sb2S5 and sulphur S. Wash the precipitate with a little hydrogen sulphide H2S water and reject washing.
2AsS43- + 6H+ ⟶ As2S5 ↓ + 3H2S ↑
2SbS43- + 6H+ ⟶ Sb2S5 ↓ + 3H2S ↑
SnS32- +2H+ ⟶ SnS2 ↓ + H2S ↑
Separation of Arsenic: Sulphides of arsenic are insoluble in concentrated hydrochloric acid HCl while sulphides of antimony and tin are soluble in it by forming chlorides. Transfer the precipitate in a conical flask and add 5-10ml concentrated hydrochloric acid HCl then place a funnel in the mouth of flask. Boil gently for 5 minutes. Sulphides of antimony and tin will dissolve and you will get arsenic sulphide as residue. Some of the arsenic may have dissolved in it, to re-precipitate it add 2-3ml water and pass hydrogen sulphide H2S gas for 1 minute. Keep the filtrate to test for antimony and tin.
Tests for arsenic: Arsenic is found in two states As(III) and As(V). In strongly acidic medium As(III) is stable and in strongly alkaline medium As(V) predominates. As(V) exists in solutions as AsO43- ion.
Dissolve the precipitate in 3-4ml warm ammonia NH3 solution. Add 3-4ml 3% hydrogen peroxide H2O2 solution and warm for a few minutes, it oxidizes arsenite As(III) to arsenate As(V). Add 1-2ml of magnesium nitrate reagent (a solution of Mg(NO3)2, NH4Cl and a little NH3). A whilte precipitate of magnesium ammonium asenate Mg(NH4)AsO4.6H2O is obtained.
AsO43- + Mg2+ + NH4+ ⟶ Mg(NH4)AsO4↓
Filter off this white precipitate and add 1ml silver nitrate AgNO3 solution containing 6-7 drops of 2M acetic acid CH3COOH. Red precipitate of silver arsenate Ag3AsO4 is formed.
Mg(NH4)AsO4 ↓ + 3Ag+ ⟶ Ag3AsO4 ↓ + Mg2+ + NH4+
Scheme for the separation of IInd group cations |
Test for Sb and Sn: Take the filtrate to test for Sb and Sn. Boil to expel H2S gas then cool it. Divide the solution into three parts. In two parts we will test for Sb and in third part for Sn.
Part 1: add 2M ammonia NH3 solution to make it just alkaline. Ignore any slight precipitation and add 1-2g solid oxalic acid (COOH)2, boil and pass H2S gas for 1 minute into hot solution. Orange precipitate of Sb2S3 is obtained.
Part 2: place 1ml solution in a spot plate and add a minute crystal of sodium nitrite NaNO2 to oxidise Sb(III) to Sb(V) state. Add 1ml of Rhodamine-B reagent (tetraethylrhodamine). A bright red colour of reagent is changed to violet.
Part 3: Partly neutralise the solution with 2M ammonia NH3 solution. Take 1m solution add 1cm clean iron wire, warm gently to reduce Sn(IV) to Sn(II).
Sn4+ + Fe ⟶ Fe2+ + Sn2+
Filter it and pour into a solution of mercury(II) chloride. Tin reduces Hg(II) to Hg(I) state and you will obtain a white precipitate of mercury(I) chloride Hg2Cl2.
Sn2+ + 2HgCl2 ⟶ Hg2Cl2 ↓ + Sn4+ + 2Cl-
If Sn2+ ions are in excess, the precipitate turns grey on warming, because of further reduction of Hg(I) ion to Hg metal.
Sn2+ + Hg2Cl2 ↓ ⟶ Hg↓ + Sn4+ + 2Cl-
In the next post we will discuss identifying tests for 3rd group cations in the filtrate you got after the removal of precipitate of 2nd group cations.
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